Question 646233
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
 y = x^2-10x+24    ||Completing Square to put Parabolic function in Vertex form
 y = (x-5)^2 - 25 + 24
 y = (x-5)^2 - 1  V(5,-1)
Graph y = (x-5)^2 - 1  and determine where the function is > 0
{x | x < 4  or x > 6}

{{{drawing(300,300,   -6, 10, -6, 6,  blue(line(5,6,5,-6))  , grid(1),
circle(5, -1,0.3), 
graph( 300, 300, -6, 10, -6, 6,0,(x-5)^2 - 1))}}}