Question 646132

I need to create a linear equation that shows how old I will be when I am 3 times my daughters age. Currently, I am 45 to her 11 and I was 34 when she was born. For some reason this math escapes me and if possible I would like each step explained so that I will be able to do the next one without help (high expectations on my part). I appreciate any help that you can offer.
Lisa 


Let the age that you will be when you're 3 times your daughter's age be A.
Since you're currently 45 and she's currently 11, a 34-year age difference exists. This means that your daughter will always be 34 years younger than you, which also means that when you're A years-old, she will be (A - 34) years-old. 


This means that the age that you will be when you're 3 times your daughter's age, equals 3 times your daughter's age then, or algebraically:


A = 3(A - 34)
A = 3A - 102
A - 3A = - 102
- 2A = - 102


A, or age that you will be when you're 3 times your daughter's age = {{{(- 102)/- 2}}}, or {{{highlight_green(51)}}}


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Your age then (51) will be 3 times your daughter's age then (A - 34, or 51 - 34, or 17)


51 = 3(17)


51 = 51 (TRUE)


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