Question 646128
A bullet is fired horizontally at a target, and the sound of its impact is
 heard 1.5 seconds later.

If the speed of the bullet is 3300ft/sec and the speed of sound is
 1100ft/sec , how far away is the target?
:
Let d = distance to the target
Write a time equation: time = dist/speed
:
Bullet transit time + sound return time = 1.5 sec
{{{d/3300}}} + {{{d/1100}}} = 1.5
multiply eq by 3300, results
d + 3d = 3300(1.5)
4d = 4950
d = 4950/4
d = 1237.5 ft