Question 646145
{{{x+4/5=-4/5y }}}

{{{(4/5)y=(-x+4/5) }}}

{{{(4/cross(5))y=(-5x+4)/cross(5) }}}

{{{4y=(-5x+4) }}}

{{{y=(-5x+4)/4 }}}

{{{y=(1/4)(-5x+4) }}}

{{{y=(1/4)(-5x)+4(1/4) }}}

{{{y=-(5/4)x+1 }}}............the slope intercept form: slope is {{{m=-(5/4)}}} and {{{y-intercept}}} is at ({{{0}}},{{{1}}})

if {{{y=0}}}, then {{{0=-(5/4)x+1 }}}...=>...{{{(5/4)x=1 }}}=>...{{{5x=4 }}}=>...{{{x=4/5 }}}

{{{x-intercept}}} is at ({{{4/5}}},{{{0}}})

 {{{ graph( 600, 600, -10, 10, -10, 10, -(5/4)x+1) }}}