Question 645738
<font face="Times New Roman" size="+2">


The problem says, "nickels, dimes, and quarters"; all plural, hence there must be at least 2 of any of them.


If there are 2 quarters, then there are 5 dimes making $1.00, so there are 20 nickels.


If there are 3 quarters, then there are 6 dimes making $1.35, so there are 13 nickels.


If there are 4 quarters, then there are 7 dimes making $1.70, so there are 6 nickels.


If there are 5 quarters, then there are 8 dimes making $2.05 -- oops! Too much.


Hence there are exactly three possibliities, 2, 3, or 4 quarters and the resulting number of dimes and nickels.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>