Question 645725
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Let *[tex \LARGE x] be the amount invested at 16%.  Then the amount invested at 14% has to be *[tex \LARGE 8800\ -\ x].  The amount received on the 16% investment is *[tex \LARGE 0.16x] and the amount received on the 14% investment is *[tex \LARGE 0.14(880\ -\ x)].  Just add the two amount quantities, set the sum equal to the total amount of interest received.  Solve for *[tex \LARGE x].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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