Question 59156
105a^3b+27a^2b^2-33ab^3
1st: Find the largest common factor in the numbers:
It is 3
2nd: Find the largest common factor in powers of "a":
It is a
3rd Find the largest common factor in powers of "b":
It is b
4th:
Factor out the common factor:
It is 3ab
You get 3ab(35a^2+9ab-11b^2)
This is the most factoring you can do with 
this algebraic expression.  How do we know
that?
We can't find two numbers whose product is 
35*-11=-385 and whose sum is 9
Chers,
Stan H.