Question 645387
One of the two digits of a two digit number, is 3 times the other digit.
 If u inter change the digit of this two digit number and add the resulting
 number to original number, you get 88. Find original number
:
Write the two digit number as 10x + y
:
"One of the two digits of a two digit number, is 3 times the other digit."
x = 3y
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If u inter change the digit of this two digit number, and add the resulting
 number to original number, you get 88.
(10y + x) + (10x + y) = 88
Combine like terms
11y + 11x = 88
Simplify, divide by 11
y + x = 8
We know x = 3y, therefore
y + 3y = 8
4y = 8
y = 8/4
y = 2 is the units digit
then
x = 3(2)
x = 6 is the 10's digit
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62 if the original number
:
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We can confirm this: 62 + 26 = 88