Question 645499
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If the radius is 12 then the circumference is 12 times 2*[tex \LARGE \pi] or *[tex \LARGE 24\pi].  *[tex \LARGE 6\pi] is one-fourth of the circumference, so that angle has to be one-fourth of the circle.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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