Question 7319
I'm not quite certain if your problem is {{{1/8-3/4x}}}={{{1/16}}} or {{{1/8-3/4}}}x={{{1/16}}}.  I'll solve both




IF IT IS:  {{{1/8-3/4x}}}={{{1/16}}}
{{{-3/4x}}}={{{1/16-1/8}}}
{{{-3/4x}}}={{{1/16-2/16}}}
{{{-3/4x}}}={{{-1/16}}}
multiply both sides by {{{-4x/3}}}
{{{(-4x/3)}}}{{{(-3/4x)}}}={{{(-4x/3)}}}{{{(-1/16)}}}
1={{{x/12}}}
multiply both sides by 12
(12)1={{{x/12}}}(12)
12=x





IF IT IS:  {{{1/8-3/4}}}x={{{1/16}}}.
{{{2/16}}}-{{{(3)(4)/16}}}x={{{1/16}}}
{{{2/16}}}-{{{(12/16)}}}x={{{1/16}}}
Multiply everything by 16
(16){{{(2/16)}}}-(16){{{(12/16)}}}x=(16){{{1/16}}}
2-12x=1
add 12x to both sides
(2-12x)+12x=(1)+12x
2=1+12x
subtract 1 from both sides
(2)-1=(1+12x)-1
1=12x
Multiply both sides by {{{(1/12)}}}
(1){{{(1/12)}}}=(12x){{{(1/12)}}}

{{{(1/12)}}}=x