Question 59133
I'm not sure where the second fraction ends, let me know if I didn't interpret you correctly.
{{{2/x-2/2x+3=1}}}
{{{2/x-2/2x+3-3=1-3}}}
{{{2/x-2/2x=-2}}}  We need a common denominator to add and subtract fractions, so:
{{{2*2/2x-2/2x=-2}}}
{{{4/2x-2/2x=-2}}}
{{{(4-2)/2x=-2}}}
{{{2/2x=-2}}}
{{{1/x=-2}}}
{{{x*1/x=-2*x}}}
{{{1=-2x}}}
{{{1/-2=-2x/-2}}}
{{{-1/2=x}}}
{{{highlight(x=-1/2)}}}
Happy Calculating!!!