Question 645386
Ans:3 5 7 9

suppose the numbers are: (a-3d),(a-d),(a+d),(a+3d)

We know that sum=s=n/2{2(a-3d)+(n-1)*2d}
here,
s=24 and
n=4
so from this expression a=6

according to the question (a-3d)(a-d)(a+d)(a+3d)=24
solving this by putting a=6
we get d=1
putting the values of a and d,
we get numbers as follows 3,5,7,9