Question 645273
{{{f(x)=-2x^2-16x-35 }}}

1.
since {{{-2}}} is less than zero, the parabola opens downward and has a global {{{maximum}}} value

2. complete the square

*[invoke completing_the_square -2, -16, -35]


Notice how the vertex is at({{{-4}}},{{{-3}}})-global {{{maximum}}}.