Question 645228
Find three consecutive integers such that four times the sum of all three is two times the product of the larger two.
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1st: x-1
2nd: x 
3rd: x+1
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Equation:
4(3x) = 2(x(x+1))
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12x = 2x^2 + 2x
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6x = x^2 + x
x^2 - 5x = 0
Factor:
x(x-5) = 0
x = 0 or x = 5
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If x = 0 the integers are: -1,0,1
If x = 5 the integers are: 4,5,6
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Cheers,
Stan H.
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