Question 645132
An isosceles triangle has two equal sides of equal length. The length of one of the equal sides is two more than 3 times the length of the third side. If the perimeter is 46 m, find the length of each side.
<pre>
Length of the unequal side = x
Length of the first equal side = 3x+2 
Length of the second equal side = 3x+2

Perimeter = {{{(matrix(5,1,

length,of,the,unequal,side))}}} + {{{(matrix(6,1,

length,of,the,first,equal,side))}}} + {{{(matrix(6,1,

length,of,the,second,equal,side))}}}

       46 = x + (3x+2) + (3x+2)

Solve that equation and get x=6 for the unequal side and
3x+2 = 3(6)+2 = 18+2 = 20

So the sides are 6m,20m,20m.

Checking: Those add to 46 and 20 is 2 more than 3×6 m, or 18m.

Edwin</pre>