Question 645126
Let x = original side


x goes to x+15 for one pair of sides while the other pair become x-13


So 


A = LW


60 = (x+15)(x-13)


(x+15)(x-13) = 60


x^2 + 2x - 195 = 60


x^2 + 2x - 195 - 60 = 0


x^2 + 2x - 255 = 0


(x+17)(x-15) = 0


x+17 = 0 or x-15 = 0


x = -17 or x = 15


Toss out the negative solution to get x = 15 as the only solution.


So the square has a side length of 15 meters. 


The area of this square is 15^2 = 15*15 = 225 square meters.


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