Question 645035
A tire is rotating 900times per min. Through how many degrees does a point on the edge of a tire move in 1/3 seconds?
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900rev/min*360º/rev*min/60 sec=900*360º/60 sec=5400º/sec
Degrees a point on the edge of the tire move in 1/3 seconds=1/3*5400º/sec=1800º