Question 644759
solve the following equation using the quadratic formula: {{{ sqrt( 3 )x^2+sqrt( 3 )=6x}}}
√3x^2+√3=6x
divide both sides by √3 (note: squaring both sides will add extraneous roots)
x^2+1=6x/√3
x^2-6x/√3+1=0
solve by the following quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
a=1, b=-6/√3, c=1
ans:
x≈0.3178
or
x≈3.1463