Question 644667
{{{ x^2-2x-3= sqrt( 4 ) }}}................recall that {{{sqrt( 4 )=2 }}}

{{{ x^2-2x-3= 2 }}}

{{{ x^2-2x-3-2=0 }}}

{{{ x^2-2x-5=0 }}}.........use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-(-2) +- sqrt( (-2)^2-4*1*(-5) ))/(2*1) }}}

{{{x = (2 +- sqrt( 4+20 ))/2 }}}

{{{x = (2 +- sqrt( 24 ))/2 }}}


{{{x = (2 +- 4.89)/2 }}}

solutions:

{{{x = (2 + 4.89)/2 }}}

{{{x = 6.89/2 }}}

{{{x = 3.45}}}

or

{{{x = (2 -4.89)/2 }}}

{{{x = -2.89/2 }}}

{{{x =-1.45}}}

{{{ graph( 600, 600, -10, 10, -10, 10, x^2-2x-5) }}}