Question 59080
I'm thinking this must be a complex fraction like this, if not scroll down to the bottom and I'll show you how to finish what you started.
{{{((x^2-2x-3)/(x^2-x-2))/((x^2-4x+3)/(x^2+5x-6))}}}
:
{{{(((x-3)(x+1))/((x-2)(x+1)))/(((x-3)(x-1))/((x+6)(x-1)))}}}
:
{{{(((x-3)*cross((x+1)))/((x-2)*cross((x+1))))/(((x-3)*cross((x-1)))/((x+6)*cross((x-1))))}}}
:
{{{((x-3)/(x-2))/((x-3)/(x+6))}}}  You can multiply both the numerator and the denominator by the LCD of both fractions (x-2)(x+6)
:
{{{((x-3)(x-2)(x+6)/(x-2))/((x-3)(x-2)(x+6)/(x+6))}}}
:
{{{((x-3)*cross((x-2))(x+6)/cross((x-2)))/((x-3)(x-2)*cross((x+6))/cross((x+6)))}}}
:
{{{(x-3)(x+6)/((x-3)(x-2))}}}
{{{cross((x-3))(x+6)/(cross((x-3))(x-2))}}}
{{{highlight((x+6)/(x-2))}}}
:
I think this would have been easier to have solved it simply as the division of two fraction rather than a complex fraction:
You got to:
{{{(x-3)/(x-2)}}} all divided by {{{(x-3)/(x+6)}}}  Flip the second fraction over and multiply:
{{{((x-3)/(x-2))*((x+6)/(x-3))}}}
{{{(cross((x-3))/(x-2))*((x+6)/cross((x-3)))}}}
{{{highlight((x+6)/(x-2))}}}
You can use either method.  Sometimes one's easier and sometimes the other's easier.
Happy Calculating!!!