Question 644600
Use the distance formula



d = sqrt((x2-x1)^2+(y2-y1)^2)



Remember that the two generic points are (x1, y1) and (x2, y2)


So (x1, y1) = (-2, 3), which means x1=-2 and y1=3


and (x2, y2) = (1, -1), which means x2=1 and y2=-1



So in short, x1=-2, y1=3, x2=1, and y2=-1.


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d = sqrt((x2-x1)^2+(y2-y1)^2)



d = sqrt((1-(-2))^2+(-1-3)^2)



d = sqrt((1+2)^2+(-1-3)^2)



d = sqrt((3)^2+(-4)^2)



d = sqrt(9+16)



d = sqrt(25)



d = 5



So exact distance between the two points is  5  units.


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