Question 644574
{{{3x^2 + 12x = 0}}}


{{{3x(x + 4) = 0}}}


{{{3x=0}}} or {{{x + 4 = 0}}}


{{{x=0}}} or {{{x = -4 }}}


So the solutions are {{{x=0}}} or {{{x = -4 }}}


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