Question 644481
Here is the problem (-2x^6y^-2/5z^3)^-2

I got down to (-2x^6y^-2)^-2/(5z^3)^-2

Then down to (5z^3)^2/(-2x^6y^-2)^2

Finally I am at 25z^6/4x^12y^-4

How am I suppose to get exponent of negative -4 to positive 4.
---------
Multiply NUM and DEN by y^4
==================
{{{(-2x^6y^-2/5z^3)^-2}}}
= {{{(5z^3/(-2x^6y^-2))^2}}}
= {{{25z^6/(4x^12y^-4)}}}
= {{{25z^6y^4/4x^12}}}