Question 644178
how to find the cube of 3x-1/3y
please reply with steps
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{{{(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3}}}
a = 3x, b = (-y/3)
{{{(3x - y/3)^3 = 27x^3 - 9x^2y + xy^2 - y^3/27}}}