Question 644168
solve for x
3^5x 9^(x^2) =27
change all terms to base 3
3^5x*3^2x^2=3^3
3^(2x^2+5x)=3^3
2x^2+5x=3
2x^2+5x-3=0
(2x-1)(x+3)=0
x=1/2
or
x=-3