Question 59042
{{{r=(0.75V/(pi))^(1/3)}}}

substitute the volume into the equation to get the revise equation
{{{r=(0.75(32pi/3)/(pi))^(1/3)}}}

because there is a {{{pi}}} on the top and bottom they cancel to give the equation
{{{r=(0.75(32)/3)^(1/3)}}}
at this stage you can simplify the brackets
{{{r=(8)^(1/3)}}}
now you can solve the equation for r

{{{r=2}}}

The radius of the spherical tank is 2m