<PRE><B>Question 644106</B>
At 2:30 pm, two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 pm?
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Faster car DATA:
distance = x miles ; time = 2.5 hrs ; rate = x/2.5 mph
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Slower car DATA:
distance = 240-x ; time = 2.5 hrs ; rate = (240-x)/2.5 mph
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Equation:
faster - slower = 10 mph
x/2.5 - (240-x)/2.5 = 10
x - 240 + x= 25
2x = 265
x = 132.75 miles
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Faster rate = 132.75/2.5 = 53.1 mph
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Slower rate = (240-132.75)/2.5 = 42.9 mph
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Rounding off the numbers you get 53 mph and 43 mph
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Cheers,
Stan H. </PRE>