Question 644056
{{{ x - 2sqrt (x) = 3 }}}


{{{-2sqrt (x) = 3-x }}}


{{{2sqrt (x) = x-3 }}}


{{{(2sqrt (x))^2 = (x-3)^2 }}}


{{{4x = (x-3)^2 }}}


{{{4x = x^2 - 6x + 9 }}}


{{{0 = x^2 - 6x + 9 - 4x }}}


{{{0 = x^2 - 10x + 9 }}}


{{{x^2 - 10x + 9 = 0 }}}


{{{(x-9)(x-1) = 0 }}}


{{{x-9=0}}} or {{{x-1=0}}}


{{{x=9}}} or {{{x=1}}}


So the *possible* solutions are {{{x=9}}} or {{{x=1}}}


Make sure you check them (I'll let you do this) to see if they are truly the solutions.