Question 643796

3•18t˛ when t = 1/3 


{{{3*18t^2}}}


{{{3*18(1/3)^2}}} ---- Substituting {{{1/3}}} for t


{{{3*18(1/9)}}}


{{{3*2cross(18)(1/cross(9))}}}


With t = {{{1/3}}}, 3•18t˛ = {{{highlight_green(6)}}}


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