Question 643834
{{{x/(2x+2)=-2x/(4x+4)+(2x-3)/(x-4)}}}...first factor out {{{2}}} in {{{(2x+2)}}}and {{{4}}} in {{{(4x+4)}}}


{{{x/2(x+1)=-2x/4(x+1)+(2x-3)/(x-4)}}}...right side has denominators {{{4(x+1)}}} and {{{(x-4)}}}...their LCD is their product (they have no common factors)


{{{x/2(x+1)=-(2x(x-4)+(2x-3)*4(x+1))/(4(x+1)(x-4))}}}


{{{x/2(x+1)=-(2x^2-8+(2x-3)*(4x+4))/(4(x+1)(x-4))}}}


{{{x/2(x+1)=-(2x^2-8+8x^2+8x-12x-12)/(4(x+1)(x-4))}}}


{{{x/2(x+1)=-(10x^2-4x-20)/(4(x+1)(x-4))}}}


{{{x/2(x+1)=-2(5x^2-2x-10)/(4(x+1)(x-4))}}}


{{{x/2(x+1)=-cross(2)(5x^2-2x-10)/(cross(4)2(x+1)(x-4))}}}


{{{x/2(x+1)=-(5x^2-2x-10)/(2(x+1)(x-4))}}}