<PRE><B>Question 643805</B>
 A diesel train left Washington and traveled toward Johannesburg at an
 average speed of 52 mph.
 A cattle train left two hours later and traveled in the same direction
 but with an average speed of 60 mph.
 Find the number of hours the diesel train traveled before the cattle train
 caught up.
:
Let t = travel time of the diesel train
then
(t-2) = travel time of the cattle train (Left 2 hrs later)
:
When the cattle train catches the diesel, they will have traveled the
 same distance. Write a distance equation. Dist = speed * time
52t = 60(t-2)
52t = 60t - 120
120 = 60t - 52t
120 = 8t
t = 120/8
t = 15 hrs
:
:
Confirm this by finding the distance of each, should be equal
52(15) = 780 mi
60(13) = 780 mi also</PRE>