Question 7249
Let d = the distance the object has fallen.
Let t = the time it takes for the object to fall distance, d.

Then, you can write:

{{{d = kt^2}}}  Now you need to find the value of k.  Substitute the given values of t = 6 secs. and d = 1296 ft.

{{{1296 = k(6)^2}}}
{{{1296 = 36k}}} Divide both sides by 36.
{{{(1296/36) = k}}}
{{{36 = k}}}

Now you need to find the time, t, the object takes to fall 2304 ft. Solve the distance formula for t.

{{{t = sqrt(d/k)}}} Substitute d = 2304 and k = 36 and solve for t.

{{{t = sqrt(2304/36)}}}
{{{t = (48/6)}}}
{{{t = 8 secs.}}}