Question 643298
<pre>
{{{c/2}}} - 5 = 11

Add "+ 5" to both sides to get rid of the "- 5" on the left:

{{{c/2}}} - 5 = 11
  + 5  + 5
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{{{c/2}}}     = 16

Multiply both sides by 2 to get rid of the denominator 2 on the left:

  2·{{{c/2}}} = 2·16

The 2's cancel on the left leaving just "c".  2·16 on the right gives 32

    c = 32

Edwin</pre>