<PRE><B>Question 643253</B>
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Depends.


Is that 2/3 times y, that is:  (2/3)y + k = j


or is it 2 divided by 3y, that is:  2/(3y) + k = j?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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