<PRE><B>Question 643226</B>
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Let *[tex \LARGE x] represent the &quot;number of years ago&quot;.  The older guy is *[tex \LARGE 50\ -\ x] at that time, and the younger is *[tex \LARGE 30\ -\ x] at that time and we know that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 50\ -\ x\ =\ 2(30\ -\ x)]


Solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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