<PRE><B>Question 642547</B>
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Write the given number as the numerator.  Write 1 as the denominator.  Counting the number of times you move it, move the decimal point in the numerator to the right all the way to the end of the given digits.  Add a number of zeros equal to the number of places you moved the numerator decimal point to the 1 in the denominator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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