Question 642541
{{{h^2 = (t-3)/(2t+5)}}}


{{{h^2(2t+5) = t-3}}}


{{{2th^2+5h^2 = t-3}}}


{{{2th^2 = t-3-5h^2}}}


{{{2th^2 - t = -3-5h^2}}}


{{{t(2h^2 - 1) = -3-5h^2}}}


{{{t = (-3-5h^2)/(2h^2 - 1)}}}


So the answer is {{{t = (-3-5h^2)/(2h^2 - 1)}}}