Question 642313
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Let *[tex \LARGE x] represent the smaller of the two consecutive positive odd integers.  Then *[tex \LARGE x\ +\ 2] is the next consecutive odd integer.


Sum of the squares:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ (x\ +\ 2)^2\ =\ 130]


A little algebra music, Sammy:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ +\ 4x\ -\ 126\ =\ 0]


Solve the factorable quadratic for the positive root, then calculate *[tex \LARGE x\ +\ 2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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