Question 642240
The tens digit, increased by 1, is still a positive integer.
If it is {{{1/8}}} of the original number,
then the original number must be a multiple of {{{8}}}.
There are 11 multiples of {{{8}}} that are two digit numbers:
16, 24, 32, 40, 48, 56, 64, 72, 80, 88, and 96.
There is only one of those whose digits add up to {{{5}}}.
{{{3+2=5}}}
The number is {{{highlight(32)}}}.
And, indeed, if you add {{{1}}} to {{{3}}} (the tens digit) you get
{{{1/8}}} of the original number.
{{{3+1=4=32/8}}}