Question 58901
Solve the following equation for x.
23x^2 + 17x= -11
23x^2 + 17x + 11=0
I get that there is no solution b/c this can't be factored. Correct? 
The determinant, b^2-4ac, is negative; that tells you the factors
involve complex numbers.  It can be factored but not in the Real 
Number System.
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The other is 1 + radical(x-5) =0
I dont have the radical symbol. Just to be clear, x-5 is under the radical.
sqrt(x-5)=-1
The square root cannot be negative; so the equation has no solution
in the Real Number System.
Cheers,
Stan H.