Question 642006
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The sum of the angles in any triangle is 180 degrees.  Hence, given angle A and angle B, you can calculate angle C.  Then use the Law of Sines:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{a}{\sin\,A}\ =\ \frac{b}{\sin\,B}\ =\ \frac{c}{\sin\,C}]


from which you can derive


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ \frac{c\,\cdot\,\sin\,A}{\sin\,C}]


The rest is a little calculator work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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