Question 642004
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You haven't solved for *[tex \LARGE x] if you still have an *[tex \LARGE x] in both sides.


From the top:  Add *[tex \LARGE -x] to both sides.


Factor *[tex \LARGE x] out of the two terms in the LHS.


Multiply both sides by *[tex \LARGE \frac{1}{2y\ -\ 1}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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