Question 641842
20-[4+8y-4(y+3)]=-3(5y-6)-[9(y-1)-14y+11]


20-[4+8y-4y-12]=-3(5y-6)-[9y-9-14y+11]


20-[4y-8]=-3(5y-6)-[-5y+2]


20-4y+8=-15y+18+5y-2


-4y+28=-10y+16


-4y+28+10y=-10y+16+10y


-4y+28+10y=16


-4y+28+10y-28=16-28


-4y+10y=16-28


6y=-12


6y/6=-12/6


y = <font color="red">-2</font>


So the solution is y = <font color="red">-2</font>


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