Question 641762
Solve for x:
{{{9^(x-1)*81^(2x-1) = 27^(3x-2)}}}
First, find the common base, that's 3:
{{{(3^2)^(x-1)*(3^4)^(2x-1) = (3^3)^(3x-2)}}} Simplify:
{{{3^(2x-2)*3^(8x-4) = 3^(9x-6)}}} Simplify more:
{{{3^(10x-6) = 3^(9x-6)}}} Now since the bases are equal, the exponents must be equal, so...
{{{10x-6 = 9x-6}}} Solve for x:
{{{x-6 = -6}}}
{{{highlight(x = 0)}}}