Question 641238
(4x+4)/(x^2-1) 
factoring the numerator:
4(x+1)/(x^2-1)
notice, for the denominator, we can rewrite as:
4(x+1)/(x^2-1^2)
it is a "difference of squares"-- special factoring case:
4(x+1)/[(x-1)(x+1)]
canceling like-terms:
4/[(x-1)]
4/(x-1)