Question 641018
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-2,-1\right)]. So this means that {{{x[1]=-2}}} and {{{y[1]=-1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,3\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3--1)/(6--2)}}} Plug in {{{y[2]=3}}}, {{{y[1]=-1}}}, {{{x[2]=6}}}, and {{{x[1]=-2}}}



{{{m=(4)/(6--2)}}} Subtract {{{-1}}} from {{{3}}} to get {{{4}}}



{{{m=(4)/(8)}}} Subtract {{{-2}}} from {{{6}}} to get {{{8}}}



{{{m=1/2}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-2,-1\right)] and *[Tex \LARGE \left(6,3\right)] is {{{m=1/2}}}



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