Question 640768

I need to find the quotient and remainder for (4x^3-5x^2+2x-6)/(x^2-3x). I know how to divide polynomials, but what is throwing me off is the (x^2-3x) part. Should I factor that out or can I just divide the first polynomial by that and solve? Do I need to instead divide by 0x^3+x^2-3x because the first polynomial has an exponent with a power of 3? It may just be easier if you would take me through it step by step instead. Thank you so much. 


You simply set this up as long-division of a polynomial, with {{{4x^3 - 5x^2 + 2x - 6}}} as the dividend, and {{{x^2 - 3x}}} as the divisor. It's somewhat difficult to demonstrate it here.


I'll start you off though.


When you do the 1st division, the 1st of the quotient-expression is 4x, which when multiplied by {{{x^2 - 3x}}} gives you: {{{4x^3 - 12x^2}}}


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