Question 640753
George and Bill left town A for town B at the same time.
 George was riding a bicycle at a constant speed, while Bill was driving a car
 Bill traveled 5 times faster than George.
 Bill’s car broke halfway, and the rest of the way to the town B Bill traveled
 by foot with a speed equal to half of the George’s bicycle speed.
 Who got to B first: George or Bill?
:
Let b = George's biking speed
then
5b = Bill's driving speed
and
.5b = Bill's walking speed
:
let d = distance from A to B
:
George's travel time equation
t = {{{d/s}}}
:
Bill's total travel time
t = {{{(.5d)/(5s)}}} + {{{(.5d)/(.5s)}}}
:
t = {{{(.5d + 10(.5d))/(5s)}}} = {{{(.5d+5d)/(5s)}}} = {{{(.1d+d)/s}}} = {{{(1.1d)/s}}}
From this we see that George's time is less than Bills, so will get to B first..