Question 640797
please help me to solve this..
find the maximum and minimum values of f(x)=x^3-6x^2+24x+4
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f(x)=x^3-6x^2+24x+4
f'(x)= 3x^2 - 12x + 24 = 0
--> x = 2 ± 2i 
No max or min
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