Question 640608
{{{2/3+3m/5=31/15}}} Start with the given equation.



{{{15(2/cross(3)+3m/cross(5))=15(31/cross(15))}}} Multiply both sides by the LCD {{{15}}} to clear any fractions.



{{{10+9m=31}}} Distribute and multiply.



{{{9m=31-10}}} Subtract {{{10}}} from both sides.



{{{9m=21}}} Combine like terms on the right side.



{{{m=(21)/(9)}}} Divide both sides by {{{9}}} to isolate {{{m}}}.



{{{m=7/3}}} Reduce.



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Answer:


So the solution is {{{m=7/3}}}